Operators

Task Discussion

• 

  Fer said:

  Rectangle area...
  http://dpaste.com/hold/1424686/

  on Oct. 21, 2013, 11:28 a.m.
  
• 

  v4lent1na said:

  Uhm I'm really bad at math - actually, I suck. Can someone please explain to me in simple and plain language how to create the program needed for the exercise? Assume that I'm a little kid and take a step-by-step instructions approach. Thanks a million!

  on Sept. 9, 2013, 8:25 a.m.
  
  

  algotruneman said:

  The key is to write the formula as math first (I do realize you need to know the formula).

  Area equals the height of rectangle times the width of rectangle.

  Math people usually say: Area = H x W which is close to the Python idea of using variables.

  Next change that to Python style code.

  areaRect = h * w

  Finally, use the inputs to get values for h and w and put the formula line after them and do a print of the answer.

  Hope that helps.

  on Sept. 9, 2013, 1:59 p.m. in reply to v4lent1na
  
  

  v4lent1na said:

  It actually helps a whole lot. I'll write it down and work around it to solve the exercise.

  Thanks! 

  on Sept. 9, 2013, 3:41 p.m. in reply to algotruneman
  
  

  v4lent1na said:

  Sorry if I bother you again: I'm gonna do this with raw_input, right?

  on Sept. 11, 2013, 5:27 a.m. in reply to algotruneman
  
  

  dvdgc said:

  In principle you could do so... though that's not asked directly.  The excercise could be understood as just doing the calculations.  But probably it's better if you ask the user, it would be more useful :)

  on Sept. 11, 2013, 4:36 p.m. in reply to v4lent1na
  
  

  algotruneman said:

  Yes, raw_input will work, but be sure to convert the input values to integer after the input.

  on Sept. 12, 2013, 6:25 p.m. in reply to v4lent1na
  
• 

  canuckfan34 said:

  Area of a Rectangle using a Function( yes, I know we haven't learned functions yet):

   

   

  def area_rectangle(length,width):

  area=length * width

  print "The area of this rectangle is:",area

  on June 26, 2013, 5:57 a.m.
  
  

  algotruneman said:

  Be sure you have the required indenting.

  def area_rectangle(length,width):

      area=length * width

      print "The area of this rectangle is:",area

  on June 26, 2013, 9:09 a.m. in reply to canuckfan34
  
  

  algotruneman said:

  Now, the nicest thing your  example did was make  me try to understand the function concept, especially the way variables get handled. I'd read about local vs. global variables, but was confused by the idea. However, trying to implement the function so I could get the results of the function to print both "inside" (as a variable local to the function) and "outside (as a global variable captured out from the function made me puzzle why my examples were not working...but now I get it!

  Thanks for spurring  me to figure it out, canuckfan34.

  Here's how I processed the information...with many trials and frustrating prints of the value of zero for the final print.

  The big key for me was seeing the difference of calling the function:
  area_rectangle(5,7)
  which shoves the two values into the function and gives variable area work inside as a local var.

  The second half of my slow realization came when I saw that the value inside not only needed a return from inside, but that the call of the function needed to be assigned to the global area variable.

  area = 0 # initializes the global variable
  def area_rectangle(length,width): # vars pulled into the function
      area = length * width
      print "The area of the rectangle is: ", area # local "inside" var
      return area
      # The next line sort of works, getting the values into the function.
      # area_rectangle(5,7) # but it doesn't work to capture the return  attempt
      # The big realization was that the inside return needed to be assigned
       # to the outside (global) variable, EVEN IF THEY WERE THE SAME VAR NAME
  area = area_rectangle(5,7) # this assignment captures the inside local
      # via the return to the outside, global area var
      # The inside area isn't the same as the outside one even though they
      # share the same human-readable name.

  print "The area (global) is: ", area
      # Over and over this stayed zero, until I saw the need to assign the
      # return value of the inside (local) to the outside (global)
      # during the function call.

  A more readable version is here: https://gist.github.com/algotruneman/5868694

  
  Thank you, canuckfan34. Your example helped me significantly advance my understanding of Python.

  on June 26, 2013, 11:42 a.m. in reply to canuckfan34
  
• 

  Iftekhar Mohammad said:

  The code is:

  http://dpaste.com/hold/1166480/

  on May 16, 2013, 4:56 a.m.
  
• 

  Dennis Daniels said:

  I did mine in Ipython3.

  The code is here.

  http://dpaste.com/1025661/

  I randomized the values to make it a little more interesting.

  on March 17, 2013, 10:03 a.m.
  
• 

  Wouter Tebbens said:

  #Use the theorem of pythagoras about rectangular triangles:
  a = raw_input ('size of side a: ')
  b = raw_input ('size of side b: ')
  print "c = ", round((float(a)**2+float(b)**2)**0.5,2)
  
  #calculate the surface of a circle
  d = raw_input('The diameter is: ')
  print "The circle's surface is: ", round(3.1415*float(d)**2/4,4)
  
  #calculate the surface of a circle
  import math
  d = raw_input('The diameter is: ')
  print "The circle's surface is: ", round(math.pi*float(d)**2/4,4)
  
  #calculate the surface of a rectangle
  length = raw_input('length: ')
  width = raw_input('width: ')
  print "The surface of the rectangle is: ", float(length)*float(width)

  on March 5, 2013, 3:11 p.m.
  
• 

  rinckemi said:

  FInding the circumference of a circle:

   

   

  print "Let's find the circumference of a circle!\n";

  r_prompt='First, what is the radius of your circle?\n';

  radius=raw_input(r_prompt);

  diameter=float(radius)*2;

  print 'So, if the radius of the circle is',radius,'that means the diameter of this circle is',diameter;

  circumference=3.14*float(diameter);

  print 'Which means that the circumference is',circumference

  on Feb. 5, 2013, 10:18 p.m.
  
• 

  drediamond said:

  How to calculate the area of a rectangle:

  j= 'What is the base of the rectangle?'

   k= raw_input (j)

  l='What is the side of your rectangle?'

  m=raw_input (l)

  print int(m)*int(k)

  on Nov. 18, 2012, 6:09 p.m.
  
• 

  0quesevayantodos0 said:

  a = 'What is the radius of your circle? '
  b = raw_input(a)
  pi = 3.14159265359
  area = float(pi)*float(b)**2

  print 'The area of your circle is ', area
   

  on Sept. 11, 2012, 11 p.m.
  
• 

  Youngestprof said:

   

  #Below is my practice

  import math

   

   

          radius = raw_input('Radius: ')

          radius = float(radius)

   

   

  area = 2 * math.pi * radius

   

  print 'Area: ',area

  on Aug. 29, 2012, 2:10 a.m.
  
• 

  Youngestprof said:

  Anyone pls help. How do i compile and run my program without using the command line that just gives results line by line?

  on Aug. 28, 2012, 3:21 p.m.
  
  

  Tyler Cipriani said:

  You just need to save your script in a file with the extension .py then run the file using python

  on Aug. 28, 2012, 3:42 p.m. in reply to Youngestprof
  
  

  Ariel said:

  hi, you can write a .py file on a text editor, and then you can play a file only with double click. 2012/8/28 twonjee2002 <

  on Aug. 28, 2012, 3:55 p.m. in reply to Youngestprof
  
  

  drediamond said:

  I use text wrangler as a free editor

  on Nov. 18, 2012, 4:58 p.m. in reply to Youngestprof
  
• 

  saravanan said:

  #Calculate the Area of a circle
  import math
  print('To Calculate the Area of a Circle')
  radius=float(input('Enter the Radius of a circle:'))
  area=math.pi*radius**2
  print('The Area of a Circle is:',format(area,'.2f'))
   

  Output:

  To Calculate the Area of a Circle
  Enter the Radius of a circle:5
  The Area of a Circle is: 78.54

  on Aug. 14, 2012, 7:14 a.m.
  
• 

  Rob said:

  script for calculating volume of sphere can be found here:

  http://dpaste.com/771135/

  on July 15, 2012, 10:03 p.m.
  
• 

  smk said:

  Calculate the area of a circle (with pi as 3.14159265359)

   

   

  # Calculate the area of a circle

   

  pi = 3.14159265359

   

  radius = float(raw_input("Enter the radius of the circle: "))

   

  print "The area is: ", pi * radius ** 2

  on July 15, 2012, 12:04 p.m.
  
• 

  Inkbug said:

  It would be nice to have both Python 2 and 3 links.

  on July 12, 2012, 8:28 a.m.
  
• 

  Inkbug said:

  Simple exponent calculator (python 3):

  x = input( "Base: " )
  y = input( "Power: " )
  print( float( x ) ** float( y ) )

  
  

  on July 12, 2012, 8:20 a.m.
  
• 

  ionut.vlasin said:

  Ex1 and 2 from the  book

  http://pastebin.com/NaTB7iN0

  and computation of rectangle area:

  http://pastebin.com/s26BDsUF

  on July 9, 2012, 10:01 a.m.
  
• 

  Andres Kwan said:

  Calculate volume and surface of a cone.

  http://pastebin.com/guDMnuw6

  on May 11, 2012, 2:33 a.m.
  
• 

  motorjunky2000 said:

  Here is my simple program to calculate area and volume of a cylinder:

  http://dpaste.com/745854/

  on May 9, 2012, 10:36 p.m.
  
• 

  Carl Burkart said:

  Here is my program to calculate the circumference and the area of a circle given the radius.  I used 22/7 for pi because I wasn't sure how to express it in python.  Corrections welcome.

  http://dpaste.com/hold/745262/

  on May 8, 2012, 10:31 p.m.
  
  

  pannix said:

  You need to import the math module and then you can use math.pi. See http://pastebin.com/EFhE4Vsa

  on May 9, 2012, 11:55 a.m. in reply to Carl Burkart